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Originally posted by Lee86
damn.. what's that maths geek's conference!?!? my head aches!!
Originally posted by ShiftyPowers
I learned it by the what two numbers multiply to equal the last number and add up to the middle number method, which is simple.
It's because I don't pay attention. I just put my head down and listen to my iPodOriginally posted by ShiftyPowers
Factoring is easy, but it depends on how it is taught to you.
Originally posted by ShiftyPowers
No, that's the confusing way, but I'll use the same example.
x^2 + 3x + 2
now since it's x^2 you know right away that it's going to be (x ____) (x ___), no 2's in there or anything.
Then you know that the last two numbers have to equal 2 when multiplied. You know this because the only multiplication in the FOIL that will equal something without "x", is the two "____"s.
In addition, you know that you're going to have one of the x's times the opposite "____" and the other x times the other "____", so basically since there are no coeficients you know it's essentially going to be "____" + "____", because you get two numbers that can be added together.
So you need two numbers that add up to 3 and multiply to 2. There's only one combination, and it's 2 and 1. Both numbers positive because -1 and -2 added together = -3. And no negative x's because of the same reason. You can technically have the factoring be (-x-2)(-x-1), but if you factor out a -1 out of each of those, they multiply to 1. Therefore the answer is (x+2)(x+1).
Basically if you look at a basic quadratic equation as AX^2+BX+C, you need two numbers that add up to B and multiply to C. If A is anything other than 1, then what you do is factor out that number. So if you have something like 2x^2+6x+4 then factor out a 2 and make it 2(x^2+3x+2), and then factor like normal, so it's 2(x+2)(x+1). And if you want to put the 2 back in, (2x+4)(x+1) or (2x+2)(x+2) are also acceptable.
Takes a lot to get factoring down for the first time, but once you get it, it's simple.
Originally posted by NIDOKING
Maths could solve anything, here is an example
A mother has 21 years more than his son, and in 6 years the kid will be five times younger than her age
Where's his father?
Analyzing
The kid has now X years old and his mom Y years old, also we know that his mother has 21 more years than him, so
X + 21 = Y
We know that in six years the kid will be five times younger than her age, so we now have
5 (X+ 6) = Y + 6
Now we replace Y with X + 21 and start calculating
5 (X + 6) = X + 21 + 6
5X + 30 = X + 27
5X - X = 27 - 30
4X = -3
X = -3/4
The kid is now -3/4 years old, that's equal to -9 months
By Maths, we discovered that someone is fücking the mother
Solution: The father is on his mother
Originally posted by NIDOKING
Maths could solve anything, here is an example
A mother has 21 years more than his son, and in 6 years the kid will be five times younger than her age
Where's his father?
Analyzing
The kid has now X years old and his mom Y years old, also we know that his mother has 21 more years than him, so
X + 21 = Y
We know that in six years the kid will be five times younger than her age, so we now have
5 (X+ 6) = Y + 6
Now we replace Y with X + 21 and start calculating
5 (X + 6) = X + 21 + 6
5X + 30 = X + 27
5X - X = 27 - 30
4X = -3
X = -3/4
The kid is now -3/4 years old, that's equal to -9 months
By Maths, we discovered that someone is fücking the mother
Solution: The father is on his mother
I got them from my professor He is a bit psycho . . .Originally posted by leungtl
Hans, are you just copying and pasting from another source.
Because you don't really show much understanding in this topic
Originally posted by jatin
U cant cancel (x-1) from both sides unless its non-zero..i.e-X!=1
Originally posted by RUSI
Can you give me an example ?
I don't know if I ever heard that ?